In the same category as Tommy's "
How To Count Cards at BlackJack" thread, this thread is an instructional guide on how to "Count Your Outs" when playing Texas Hold 'Em.
Count your "outs"? What the hell is an "out"?"Outs" are the remaining cards in the deck that can potentially win you the hand, if you're the underdog in the hand (or if you think you're the underdog in the hand).
For Example, let's say Johnny is holding two Aces - An Ace of Diamonds and an Ace of Hearts. You are holding a Jack of Spades and a 10 of Spades.Â
So, it's Ad Ah vs. Js 10s (the lowercase letters stands for the suit of the card, from here on out, so s=Spades, h=Hearts, c=Clubs, d=Diamonds).
The Flop comes a Ac, Qs, 9s. So, Johnny now has 3 Aces, but you have a straight draw (any King or 8), or a flush draw (any Spade). You also have a straight-flush draw, and you make a straight flush with either the King of spades or the eight of spades.
So, how many "outs" do you have left to turn your hand from not winning, to the winning hand?? Can you guess??
The answer is
16. There are 16 different cards that can come out on the next card that will make your hand the winning hand, at that point in time (because remember there is still one card to go).Â
You can draw any King for a straight (4 cards); any 8 for a straight (4 cards), and all but 1 spade for a flush (8 cards).  The Ace of Spades here is
NO GOOD, because while you make a flush with it, Johhny makes FOUR ACES, which beats a flush.Â
Ok so I now am aware of the exact number of cards left in the deck that can help me. How do I turn that into a percentage, so I can see what my chances are?The way to know what the percentage will be on the hand is simple.Â
Take your number of outs (in this case it's
16), multiply it by 2, and add 2.
So, the formula will be
16 x 2 + 2, which =
34, or 34%That was too complicated. Can you give me a simpler example?Fine. Player 1 is holding Kd Kh. Player 2 is holding Jd Jh. The flop is 2c, 5h, 10d. The turn is 7s. Can you calculate your outs, and then your percentage of player 2 winning the hand on the last card?
First, he has
2 outs. The only two cards player 2 can win the hand with are the two remaining Jacks in the deck. That's it, nothing else, no other card will win it for him.Â
So,
2 x 2 + 2 = 6%*. Basically, player 2 is screwed, barring a miracle
* Note - When you multiply the outs by 2, and the total is 10 or less, it is more accurate to add 1 instead of 2 at the end, but a 1% variance of deciding what you're gonna do will never change your decision, so it's not really that important.
What if I need TWO cards in a row to help my hand become the winning hand?If you need TWO consecutive cards to help your hand, ask yourself this question - what the hell are you doing in the hand anyways?
These situations are total longshots - never any greater then 10%, and that's really high for that kind of situation. If you need two consecutive cards to win the hand after the flop, you're really looking at anywhere from a 2 or 3% chance to win, to a 1 in 1,000 chance to win. Let's say you're all-in with 7, 7, and your opponent has A, K. The flop comes A, A, K. Your exact odds of catching the last two 7's in a row are exactly 989 to 1. It can happen, and has happened, but you can easily bet the farm that it won't happen, ever.
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Hope this guide helps you the next time you play Texas Hold 'Em!